Math 192—Calculus II Name
___________________________________
Prof. Hess
(From
Section 12.7)
Name
of Test |
Convergence
or Divergence |
Comments |
Test for Divergence |
If |
Inconclusive if |
Integral Test |
San and |
Can only be used if f(x) is continuous,
positive, and decreasing "x >
1. The antiderivative may be hard to find. |
Basic Comparison Test |
If Sbn converges and an < bn
"n, then San also converges. If Sbn diverges and an > bn
"n, then San also diverges. |
Can only be used if San and Sbb are both positive terms
series. Most useful when San has a form similar to a
geometric or p-series. |
Limit Comparison Test |
If |
Can only be used if San and Sbb are both positive terms
series. Most useful when San has a form similar to a
geometric or p-series. Inconclusive if c = 0 or ¥. |
Alternating Series Test |
Let
San = S(-1)n+1bn. If bn+1 < bn
"n, and if |
Applies only to alternating
series. |
Ratio Test |
Let If L < 1, then San converges absolutely. If L > 1, then San diverges. |
Inconclusive if L = 1. Most useful when San involves factorials
and/or nth powers. |
Root Test |
Let If L < 1, then San converges absolutely. If L > 1, then San diverges. |
Inconclusive if L = 1. Most useful when San involves nth
powers. |
Geometric
Series: converges to
if |r| < 1,
diverges if |r| > 1. To recognize a
geometric series, look for a fraction with one or more constants raised to the
nth power.
p-Series: converges if p >
1, diverges if p< 1. To
recognize a p-series, look for a fraction with n raised to a constant
power. The power may be “hiding” as a
radical sign.
Telescoping Series: converges to 1.
Harmonic Series: diverges.
Alternating Harmonic Series: converges
conditionally.
Error in Using the Partial Sum Sn to
Approximate the Infinite Sum S
For positive term series, (but only if f is
continuous, positive, and decreasing).
For alternating series, Rn <
bn+1
Absolute vs Conditional Convergence
Suppose San is a convergent series that contains both
positive and negative terms.
San converges absolutely
if S|an| also converges.
San converges conditionally
if S|an| diverges.
If you can show that S|an| converges, then San is automatically absolutely
convergent.
If S|an| diverges, then San is either divergent or
conditionally convergent. Apply the
Alternating Series Test to determine which.
/SeriesSummary-192