Compound interest

In the equation [Maple Math] A is the compound amount, P is the principal, r is the interest rate as a decimal, n is the number of compounding times per year, and t is time in years.

Example 1

If $100 is invested at 5% compounded quarterly, find how long it takes for the investment to double.

Solution .

Using A = 200, P =100, r = 0.05, n =4 we get [Maple Math] To solve this problem we must solve this exponential equation for t. First isolate the exponential part by dividing by 100. This gives us [Maple Math] Taking the natural log of both sides we get [Maple Math] Using property 3 we get [Maple Math] and thus [Maple Math] = 13.949 or about 14 years.

Example 2

Investor A has $100 invested at 4% compounded annually while investor B has $50 invested at 6% compounded annually. In how many years will B's investment exceed A's?

Solution .

In x years, A will have [Maple Math] while B will have [Maple Math] We solve [Maple Math] Divide both sides by 50. This gives us [Maple Math] . Now divide by [Maple Math] This yields [Maple Math] or [Maple Math] Taking the natural log of both sides and using property 3, we get [Maple Math] Solving this for x, we get x = 36.389 years. This can be seen in the graph below.

[Maple Plot]